If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-5x-1000=0
a = 1; b = -5; c = -1000;
Δ = b2-4ac
Δ = -52-4·1·(-1000)
Δ = 4025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4025}=\sqrt{25*161}=\sqrt{25}*\sqrt{161}=5\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{161}}{2*1}=\frac{5-5\sqrt{161}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{161}}{2*1}=\frac{5+5\sqrt{161}}{2} $
| -(x-3)=-x-3 | | -12(9+2p)=-4(8p+9) | | 7t^2+28t+56=140 | | X^2+3x-4=2x+4 | | 7k-40=7(k-7) | | -6p+2p=6(2p-12)-4(p-9) | | 6=1/8=a | | 25w=50 | | x(x+2)/2=84 | | F(x)=3x2+6x+6 | | 19=9-y | | 2/3+4y=0.6 | | 2x^2+3x-9=204 | | F(0)=5n^2+2n | | 0.2(t+7.8)=16.5 | | F(n)=5n^2+2n | | 2/9x+1/3=-1/3x+1/3 | | -2(3s-4)-8=-2(8s+3)-3 | | 8-7(7c+3)=-4c-1 | | 9-3(-3r-7)=6r+7 | | 12+2y=10y-17 | | 6n-5n=12 | | (3)^3x-5=1/9x | | 4(5x+2)-6=0 | | 3÷7+x=17÷7 | | 7-8x=8(1+7x) | | x÷3+4=3 | | x=15-2^x | | 2(x-4)=5/6(x+6) | | -1/6x+5-6x=52/3 | | 2x-7(-1)=11 | | y-6+y=0 |